5^(2x)=7(x-1)

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Solution for 5^(2x)=7(x-1) equation: 



5^(2x)=7(x-1)

We move all terms to the left:

5^(2x)-(7(x-1))=0



We calculate terms in parentheses: -(7(x-1)), so:

7(x-1)

We multiply parentheses

7x-7

Back to the equation:

-(7x-7)



We get rid of parentheses

5^2x-7x+7=0

We add all the numbers together, and all the variables

-7x+5^2x+7=0

We move all terms containing x to the left, all other terms to the right

-7x+5^2x=-7

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